Problem 119
In which ordered fields can the floor function be defined? Difficulty: 5. Answer (final result) is provided for this problem. |
Problem 116
Does the ordered field of rational functions satisfy the Archimedean axiom? Difficulty: 6. |
Problem 117
Given an ordered field \(\displaystyle R\) and a subfield \(\displaystyle \Q\) show that if \(\displaystyle (\forall a,b \in R) \; \bigg((1<a<b<2) \Rightarrow \Big((\exists q\in \Q) \; (a<q<b)\Big)\bigg), \) then \(\displaystyle R\) satisfies the Archimedean axiom. Difficulty: 7. |
Supported by the Higher Education Restructuring Fund allocated to ELTE by the Hungarian Government |