Problem 1379
Let \(\displaystyle \gamma:[1,2]\to\R^3\), \(\displaystyle \gamma(t)=(\ln t,2t,t^2)\). (a) Determine the length of \(\displaystyle \gamma\). (b) Determine the line integral of the vector field \(\displaystyle f(x,y,z)=(x,y,z)\) along the curve \(\displaystyle \gamma\). Difficulty: 3. |
Problem 1380
Let \(\displaystyle C\) be the geometric curve \(\displaystyle \{(x,y)|\ |x|+|y|=a\}\). \(\displaystyle \int_C xy\ \hbox{d}s=?\) Difficulty: 3. |
Problem 1381
Let \(\displaystyle \gamma: [0,2]\to \R^2\), \(\displaystyle (t)\mapsto (t,t^2)\). Compute the \(\displaystyle \int_{\gamma} (-y,x)\ \hbox{d}g\) line integral where \(\displaystyle g\) is the identity function. Difficulty: 3. |
Problem 1382
Let \(\displaystyle \gamma\) be the semicircle which is the right part of the circle centered at \(\displaystyle 0\) with radius \(\displaystyle a\) (i.e those points satsifying \(\displaystyle x\geq 0\)). \(\displaystyle \int_{\gamma} x\ \hbox{d}y=?\) Difficulty: 3. |
Problem 1383
Let \(\displaystyle \gamma\) be the semicircle which is the upper part of the circle centered at \(\displaystyle 0\) with radius \(\displaystyle a\) (i.e those points satsifying \(\displaystyle y\geq 0\)). \(\displaystyle \int_{\gamma}x^2\ \hbox{d}s=?\) Difficulty: 3. |
Problem 1386
Determine the line integral of the vector field \(\displaystyle \displaystyle\left(\frac{x}{1+y},\frac{y}{2+x}\right)\) along the parabola \(\displaystyle y=x^2\) segment between the points \(\displaystyle (-1,1)\) and \(\displaystyle (1,1)\). Difficulty: 3. |
Problem 1384
\(\displaystyle a)\quad \int_0^2 \sin x\ \hbox{d}\{x\}=?\qquad\qquad\qquad b)\quad \int_{\gamma} x^2\ \hbox{d}(y^2)=?\) where \(\displaystyle \gamma\) is the triangle with vertices \(\displaystyle (0,0), (2,0), (0,1)\). Difficulty: 4. |
Problem 1385
Calculate the line integral \(\displaystyle \int xy\;\dy\) on the curve in the figure. Difficulty: 4. |
Problem 1387
Consider a map \(\displaystyle g:[a,b]\to\R\) as a one-dimensional curve. When is it rectifiable? What is its length? Difficulty: 4. |
Problem 1388
Let \(\displaystyle g:[0,1]\to\R^2\) be a simple closed and rectifiable curve. Prove that \(\displaystyle \int_{g}x^2\;\dx = \int_{g}e^{-\cos y^2}\;\dy = 0. \) Difficulty: 4. |
Problem 1389
Let \(\displaystyle *:\R^p\times \R^q\to\R^r\) be bilinear, \(\displaystyle f:\R^q\to\R^p\) continuous and \(\displaystyle g:[a,b]\to\R^q\) a continuous curve. Show that (a) if \(\displaystyle g\) is rectifiable, then \(\displaystyle \int_g f(\mathbf{x})*\mathrm{d}\mathbf{x}\) exists; (b) if \(\displaystyle g\) is continuously differentiable, then \(\displaystyle \int_g f(\mathbf{x})*\mathrm{d}\mathbf{x}=\int_a^b f(g(t))*g'(t)\dt.\) Difficulty: 4. |
Supported by the Higher Education Restructuring Fund allocated to ELTE by the Hungarian Government |